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shader/arithmetic_integer: Change IAdd to UAdd to avoid signed overflow

Signed integer addition overflow might be undefined behavior. It's free
to change operations to UAdd and use unsigned integers to avoid
potential bugs.
ReinUsesLisp 6 năm trước cách đây
mục cha
commit
2a96bea6a7
1 tập tin đã thay đổi với 2 bổ sung2 xóa
  1. 2 2
      src/video_core/shader/decode/arithmetic_integer.cpp

+ 2 - 2
src/video_core/shader/decode/arithmetic_integer.cpp

@@ -40,12 +40,12 @@ u32 ShaderIR::DecodeArithmeticInteger(NodeBlock& bb, u32 pc) {
         op_a = GetOperandAbsNegInteger(op_a, false, instr.alu_integer.negate_a, true);
         op_b = GetOperandAbsNegInteger(op_b, false, instr.alu_integer.negate_b, true);
 
-        Node value = Operation(OperationCode::IAdd, op_a, op_b);
+        Node value = Operation(OperationCode::UAdd, op_a, op_b);
 
         if (instr.iadd.x) {
             Node carry = GetInternalFlag(InternalFlag::Carry);
             Node x = Operation(OperationCode::Select, std::move(carry), Immediate(1), Immediate(0));
-            value = Operation(OperationCode::IAdd, std::move(value), std::move(x));
+            value = Operation(OperationCode::UAdd, std::move(value), std::move(x));
         }
 
         if (instr.generates_cc) {