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shader/arithmetic_integer: Change IAdd to UAdd to avoid signed overflow

Signed integer addition overflow might be undefined behavior. It's free
to change operations to UAdd and use unsigned integers to avoid
potential bugs.
ReinUsesLisp 6 vuotta sitten
vanhempi
commit
2a96bea6a7
1 muutettua tiedostoa jossa 2 lisäystä ja 2 poistoa
  1. 2 2
      src/video_core/shader/decode/arithmetic_integer.cpp

+ 2 - 2
src/video_core/shader/decode/arithmetic_integer.cpp

@@ -40,12 +40,12 @@ u32 ShaderIR::DecodeArithmeticInteger(NodeBlock& bb, u32 pc) {
         op_a = GetOperandAbsNegInteger(op_a, false, instr.alu_integer.negate_a, true);
         op_b = GetOperandAbsNegInteger(op_b, false, instr.alu_integer.negate_b, true);
 
-        Node value = Operation(OperationCode::IAdd, op_a, op_b);
+        Node value = Operation(OperationCode::UAdd, op_a, op_b);
 
         if (instr.iadd.x) {
             Node carry = GetInternalFlag(InternalFlag::Carry);
             Node x = Operation(OperationCode::Select, std::move(carry), Immediate(1), Immediate(0));
-            value = Operation(OperationCode::IAdd, std::move(value), std::move(x));
+            value = Operation(OperationCode::UAdd, std::move(value), std::move(x));
         }
 
         if (instr.generates_cc) {