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common/scope_exit: Replace std::move with std::forward in ScopeExit()

The template type here is actually a forwarding reference, not an rvalue
reference in this case, so it's more appropriate to use std::forward to
preserve the value category of the type being moved.
Lioncash 7 лет назад
Родитель
Сommit
b569641098
1 измененных файлов с 1 добавлено и 1 удалено
  1. 1 1
      src/common/scope_exit.h

+ 1 - 1
src/common/scope_exit.h

@@ -20,7 +20,7 @@ struct ScopeExitHelper {
 
 template <typename Func>
 ScopeExitHelper<Func> ScopeExit(Func&& func) {
-    return ScopeExitHelper<Func>(std::move(func));
+    return ScopeExitHelper<Func>(std::forward<Func>(func));
 }
 } // namespace detail